Armstrong Number in C

#include<stdio.h>  
#include<conio.h>

 void main()    
{    
    int n,r,sum=0,t; 
    clrscr();//clear the screen
    printf("Enter the number: ");    
    scanf("%d",&n);    
    t=n;
    while(t>0)    
    {    
        r=t%10;    
        sum=sum+(r*r*r);    
        t=t/10;    
    }    
    if(n==sum) 
    {
        printf("%d is armstrong  number.",n);    
    }
    else 
    {
        printf("%d is not armstrong number.",n); 
    }
}

1. Start
2. Prompt the user to enter a number and read the number into variable `n`.
3. Initialize:
    - `sum` to 0 (to store sum of cubes of digits)
    - `t` to `n` (to preserve original number for comparison)
4. While `t` is greater than 0, repeat the following steps:
    - Compute `r` = `t % 10` (extract the last digit)
    - Compute `r^3` (cube of the digit)
    - Add `r^3` to `sum`
    - Update `t` to `t / 10` (remove the last digit)
5. After the loop ends, compare `sum` with the original number `n`.
6. If `sum` equals `n`, then
     - Print that `n` is an Armstrong number.
    Else
     - Print that `n` is not an Armstrong number.
7. End