Days to Years Months Days in C

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Q. Write a program to convert days into years months and days.

#include <stdio.h>
#include <conio.h> 

void main()
{
	int d, years, months, days, t;
	clrscr();
	printf("Enter number of days : ");
	scanf("%d", &d);
	years = d / 365;
	t = d % 365;
	months = t / 30;
	days = t % 30;
	printf(" %d years  %d months  %d days", years, months, days);
	getch();
}
Run ›

Q. Write an algorithm to convert days into years months and days.

START
1. Declare variables:
- d (integer): total number of days input by the user
- years (integer)
- months (integer)
- days (integer)
- t (integer) : temporary variable for remainder calculations
2. Prompt the user to "Enter number of days".
3. Read the input value into variable d.
4. Calculate the number of years:
years = d / 365
5. Calculate the remainder days after subtracting years:
t = d % 365
6. Calculate the number of months from the remainder:
months = t / 30
7. Calculate the remaining days after subtracting months:
days = t % 30
8. Display the results in the format:
" years  months  days"
END
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