Integer To Character in C

#include <stdio.h>
#include <conio.h> 

void main()
{
    int n, sum = 0;
    clrscr();
    printf("Enter the number to print in words: ");
    scanf("%d", &n);
    while(n > 0)
    {
        sum = (sum * 10) + (n % 10);
        n = n /10;
    }
    while(sum > 0)
    {
        switch(sum % 10)
        {
            case 0: 
                printf("Zero ");
                break;
            case 1: 
                printf("One ");
                break;
            case 2: 
                printf("Two ");
                break;
            case 3: 
                printf("Three ");
                break;
            case 4: 
                printf("Four ");
                break;
            case 5: 
                printf("Five ");
                break;
            case 6: 
                printf("Six ");
                break;
            case 7: 
                printf("Seven ");
                break;
            case 8: 
                printf("Eight ");
                break;
            case 9: 
                printf("Nine ");
                break;
        }
        sum = sum / 10;
    }
}

1. Start
2. Initialize an integer variable `sum` as 0.
3. Prompt the user to enter a number `n`.
4. Read the input number `n`.
5. Reverse the number `n`:
- While `n > 0`:
- Extract the last digit of `n` using `digit = n % 10`.
- Update `sum = sum * 10 + digit`.
- Remove the last digit from `n` by `n = n / 10`.
6. Print each digit of the reversed number `sum` in words:
- While `sum > 0`:
- Extract the last digit of `sum` using `digit = sum % 10`.
- Use a `switch` or `if-else` construct to print the word corresponding to `digit`:
- 0 → "Zero"
- 1 → "One"
- 2 → "Two"
- 3 → "Three"
- 4 → "Four"
- 5 → "Five"
- 6 → "Six"
- 7 → "Seven"
- 8 → "Eight"
- 9 → "Nine"
- Remove the last digit from `sum` by `sum = sum / 10`.
7. End