Palindrome Number in C

#include <stdio.h>
 
void main()
{
   int n, sum = 0, t;
   printf("Enter the number: ");
   scanf("%d", &n);
   t = n;
   while (t > 0)
   {
      sum = sum * 10 + t%10;
      t = t/10;
   }
   if (n == sum)
   {
      printf("%d is a palindrome number.", n);
   }
   else
   {
      printf("%d is not a palindrome number.", n);
   }
}

1. Start
2. Input the integer number `n`
3. Initialize an integer variable `sum` to 0.
    This will store the reversed number.
4. Initialize an integer variable `t` and assign the value of `n` to it.
    `t = n`
5. While `t` is greater than 0, repeat steps 6 to 8:
6. Get the last digit of the number `t` by using modulo operation:
    `digit = t % 10`
7. Append the digit to `sum` by shifting previous digits to the left:
    `sum = sum * 10 + digit`
8. Remove the last digit from `t` by using integer division:
    `t = t / 10`
9. Compare the original number `n` with the reversed number stored in `sum`
- If `n` is equal to `sum`, then `n` is a palindrome number.
- Else, `n` is not a palindrome number.
10. Print the result accordingly.
11. End