Sum Of Two Digits in C

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Q. Write a C program for Sum of Two Digits.

#include  
#include 
  
Void main(){    
    int a,b,c; 
    clrscr();   
    printf("Enter the numbers:");    
    scanf("%d %d",&a,&b); 
    c=a+b;
    printf("Sum Of Two Digits is: %d ",c); 
    getch();  
}
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Q. Write an algorithm to Sum of Two Digits.

1. Start
2. Declare integer variables: `n` (input number), `r` (digit), `sum`, `t` (temporary variable)
3. Initialize `sum` to 0
4. Prompt the user to enter a number and read it into `n`
5. Assign `t = n`
6. While `t` is greater than 0:
    a. Extract the last digit: `r = t % 10`
    b. Add cube of the digit to sum: `sum = sum + (r * r * r)`
    c. Remove the last digit: `t = t / 10` (integer division)
7. If `sum` equals the original number `n` then
    a. Print "`n` is an Armstrong number"
8. Else
    a. Print "`n` is not an Armstrong number"
9. End
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