Armstrong Number in C++

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Q. Write a C++ program to check Armstrong Number or Not.

#include <iostream>    
using namespace std;
  
int main()
{    
    int n,r,sum=0,t; 
    cout << "Enter the number: ";    
    cin >> n;    
    t=n;
    while(t>0)    
    {    
        r=t%10;    
        sum=sum+(r*r*r);    
        t=t/10;    
    }    
    if(n==sum) 
    {
        cout << n " is armstrong  number.";    
    }
    else 
    {
        cout << n " is not armstrong  number.";  
    }
	return 0;    
}
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Q. Write an algorithm to check Armstrong Number or Not.

1. Start
2. Input: Read integer number `n`.
3. Initialize:
    - `sum = 0`
    - `t = n` (copy of the original number)
4. Process each digit of the number:
    - While `t > 0`:
      a. Extract the last digit: `r = t % 10`
      b. Add the cube of the digit to `sum`: `sum = sum + (r * r * r)`
      c. Remove the last digit from `t`: `t = t / 10` (integer division)
5. Check if the number is Armstrong:
   - If `sum == n`, then
   - Output: "`n` is an Armstrong number."
   - Else
   - Output: "`n` is not an Armstrong number."
6. End
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