C++ Passing Array To Function Arguments

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Passing array to function argument in C++. There are three ways to approach function declaration to receive an array as the function argument.

1st Way:-

Syntax:

return_type function(type array_name[])

Example:

void smart(int par[])

2nd Way:-

Syntax:

return_type function(type array_name[Size])

Example:

void smart(int par[5])

3rd Way:-

Syntax:

return_type function(type *array_name)

Example:

void smart(int *par)

Example:-

#include <iostream>   
using namespace std;
int sumofarrayvalue(int arr[],int size){    
    int sum=0;    
    for(int i=0; i<size; i++){    
        sum+=arr[i] ; 
    }   
    return sum;    
}    
int main(){       
    int numbers[]={6,9,1,3,4,8};
    int sum;
    /* Passing pointer to the array as an argument */
    sum=sumofarrayvalue(numbers,6);
    cout << "Sum Of Array Value is " << sum; 
    return 0;    
}
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