Integer To Character in C++

#include    
using namespace std;
  
int main()
{      
    int n, sum = 0;
    cout << "Enter the number to print in words: ";
    cin >> n;
    while(n > 0)
    {
        sum = (sum * 10) + (n % 10);
        n = n /10;
    }
    while(sum > 0)
    {
        switch(sum % 10)
        {
            case 0: 
                cout << "Zero ";
                break;
            case 1: 
                cout << "One ";
                break;
            case 2: 
                cout << "Two ";
                break;
            case 3: 
                cout << "Three ";
                break;
            case 4: 
                cout << "Four ";
                break;
            case 5: 
                cout << "Five ";
                break;
            case 6: 
                cout << "Six ";
                break;
            case 7: 
                cout << "Seven ";
                break;
            case 8: 
                cout << "Eight ";
                break;
            case 9: 
                cout << "Nine ";
                break;
        }
        sum = sum / 10;
    }
	return 0;    
}

1. Start
2. Initialize variables
    - Create an integer variable `n` to store the input number.
    - Create an integer variable `sum` and set it to 0.
3. Input the number `n`
    - Prompt the user: "Enter the number to print in words: "
    - Read the integer `n`.
4. Reverse the number `n` and store in `sum`
    - While `n > 0`
    a. Extract the last digit of `n` as `digit = n % 10`
    b. Update `sum = sum * 10 + digit` (this reverses the digits)
    c. Divide `n` by 10 (integer division) to remove the last digit `n = n / 10`.
5. Print the words corresponding to each digit of reversed number (`sum`)
    - While `sum > 0`
    a. Extract last digit: `digit = sum % 10`
    b. Use a switch-case or if-else to find the word representation of the digit:
        - 0 → "Zero"
        - 1 → "One"
        - 2 → "Two"
        - 3 → "Three"
        - 4 → "Four"
        - 5 → "Five"
        - 6 → "Six"
        - 7 → "Seven"
        - 8 → "Eight"
        - 9 → "Nine"
   c. Print the corresponding word followed by a space.
   d. Remove last digit from `sum` by integer division `sum = sum / 10`.
6. End