Palindrome Number in C++

#include<iostream>        
using namespace std;
  
int main()
{  
   int n, sum = 0, t;
   cout << "Enter the number: ";
   cin >> n ;
   t = n;
   while (t > 0)
   {
      sum = sum * 10 + t%10;
      t = t/10;
   }
   if (n == sum)
   {
      cout << n <<" is a palindrome number." ;
   }
   else
   {
      cout << n <<" is not a palindrome number." ;
   }
   return 0;
} 

1. Start
2. Input the integer number `n`
3. Initialize a variable `sum` to 0
   (This will hold the reversed number)
4. Initialize a variable `t` with the value of `n`
   (This will be used to extract digits without losing original number)
5. While `t` is greater than 0, do the following:
   a. Extract the last digit of `t` by `t % 10`
   b. Update `sum` as `sum * 10 + (t % 10)`
   (This appends the extracted last digit to the reversed number)
   c. Remove the last digit from `t` by `t = t / 10` (integer division)
6. After the loop ends, compare:
   - If `sum` is equal to `n` then
      Print "`n` is a palindrome number."
   - Else
      Print "`n` is not a palindrome number."
7. End