Reverse Number in C++

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Q. Write a C++ program for Reverse Number.

#include    
using namespace std;
  
int main()
{  
   int n, sum = 0;
   cout << "Enter the number: ";
   cin >> n;
   
   while (n > 0)
   {
      sum = sum * 10 + n%10;
      n = n/10;
   }
   cout << "Reverse of number is : " << sum  ;
   return 0; 
}
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Q. Write an algorithm to Reverse Number in C++.

1. Read the input number.
2. Extract the last digit by `num % 10`.
3. Append that digit to the reversed number by `reversed = reversed * 10 + digit`.
4. Remove the last digit from `num` by `num /= 10`.
5. Repeat until `num` becomes zero.
6. Print the reversed number.
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